2x^2-29x-15x=0

Solution for 2x^2-29x-15x=0 equation:

2x^2-29x-15x=0

We add all the numbers together, and all the variables

2x^2-44x=0

a = 2; b = -44; c = 0;
Δ = b2-4ac
Δ = -442-4·2·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-44}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+44}{2*2}=\frac{88}{4}
=22
$